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Erich
Moderator
Mechanical-Engineering.com Expert
Estimates of friction at all joints,
Rate of acceleration desired as it starts up.
What loads does wind have on the structure?
Hint start with a free body diagram...……..
Rate of acceleration desired as it starts up.
What loads does wind have on the structure?
Hint start with a free body diagram...……..
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jasonmeur
New Member
Thank its Realy helpful...
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shachmat
New Member
When i selecting a motor I'm checking all the moments in the system @ each angle and literally build the movement profile.
After that its easy to understand what is the required "continues moment and what is the peak moment.
Mt=F*L for movement.
Mt= I[Kg*m^2] × alfa[rad/sec^2].for acceleration.
Here is a good guide for motor selecting:
https://www.machinedesign.com/motors-drives/article/21831643/how-to-pick-motors-for-linear-motion.
Try to think about direct drive instead of spour gear
Good luck
After that its easy to understand what is the required "continues moment and what is the peak moment.
Mt=F*L for movement.
Mt= I[Kg*m^2] × alfa[rad/sec^2].for acceleration.
Here is a good guide for motor selecting:
https://www.machinedesign.com/motors-drives/article/21831643/how-to-pick-motors-for-linear-motion.
Try to think about direct drive instead of spour gear
Good luck
O
Oilytrunk
Well-Known Member
Yup, it is indeed a good one.
Justcurioustwo
Well-Known Member
Attached is a drawing of a machine that produces 118,428 foot pounds of force traveling at a speed of three (3) feet per second.
How can I convert this to torque and then to potential electric output?
How can I convert this to torque and then to potential electric output?
Justcurioustwo
Well-Known Member
E
Erich
Moderator
Mechanical-Engineering.com Expert
Units of force are pounds or Newtons.
Foot-lbs are units of Torque or energy, not force.
Clarify what you have.
Foot-lbs are units of Torque or energy, not force.
Clarify what you have.
s.weinberg
Moderator
Mechanical-Engineering.com Expert
What he has is a thoroughly debunked basic, run-of-the-mill, perpetual motion machine.
Justcurioustwo
Well-Known Member
Thanks for your clarification.
Do you agree with the following.
To determine the SeaEngine's potential energy output I have to determine the value of two (2) things-
(1) energy it takes to compress 40,000 cubic feet of air down to 2,666.66 cubic feet in watts.
(2) energy output of 118,428 foot pound in watts.
If (watts-2)'s output is greater than (watts-1), then the SeaEngiine is producing useful work.
I believe my drawing proves that the SeaEngine is producing useful work.
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